Option ExplicitDim days As Long '<-Stores the number of days elapsed from 1/1/1900 to current month and yearDim i As Integer
Private Sub cmdGenerate_Click()On Error GoTo Error_handle 'On error, goto to end of functiondays = 0For i = 0 To 34 Label1(i).Caption = "" 'Clear all the labelsNext i
For i = 1900 To txtYear.Text - 1 If i Mod 4 = 0 Then 'If leap year then count 366 days days = days + 366 Else 'else 365 days days = days + 365 End IfNext i
For i = 1 To txtMonth.Text - 1 If i = 1 Or i = 3 Or i = 5 Or i = 7 Or i = 8 Or i = 10 Or i = 12 Then 'For January,March,May....,December count 31 days days = days + 31 ElseIf (i = 4 Or i = 6 Or i = 9 Or i = 11) Then 'For April,June,September,November count 30 days days = days + 30 ElseIf (i = 2 And txtYear.Text Mod 4 = 0) Then 'If month is February and year is leap year count 29 days days = days + 29 Else 'If month is February and year is not a leap year, count 28 days days = days + 28 End If Next i
If (i = 1 Or i = 3 Or i = 5 Or i = 7 Or i = 8 Or i = 10 Or i = 12) Then show_calender 31 'Show calender with 31 days ElseIf (i = 4 Or i = 6 Or i = 9 Or i = 11) Then show_calender 30 'Show calender with 30 days ElseIf (i = 2 And txtYear.Text Mod 4 = 0) Then show_calender 29 'Show calender with 29 days Else show_calender 28 'Show calender with 28 days End IfError_handle:End Sub
Private Function show_calender(n As Integer) '//<- n stores the number of days to displayDim i, k As Integerk = days Mod 7 'Divide days with 7, the remainder give the current dayFor i = 1 To n Label1(k).Caption = i 'Display the number in calender format k = k + 1 If k = 35 Then k = 0Next iEnd Function
Selasa, 24 Maret 2009
kaLendeR
Diposting oleh frestea di 03.14
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